An object of mass 0.2 kg executes simple harmonic oscillations along the x–axis with a frequency of (25 / π ) Hz. At the position x = 0.04m, the object has kinetic energy of 0.5 J and potential energy 0.4 J. Find the amplitude of oscillations
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(A = 0.06 m)
Total energy E = 
m ꞷ 2 A 2
0.5 + 0.4 = 
× 0.2 
A 2
⇒ 9 = (50) 2 A 2
⇒ A = 0.06 m
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